URI ONLINE JUDGE SOLUTION 1040 - Average 3
Problem
Read four numbers (N1, N2, N3, N4), which one with 1 digit after the decimal point, corresponding to 4 scores obtained by a student. Calculate the average with weights 2, 3, 4 e 1 respectively, for these 4 scores and print the message "Media: " (Average), followed by the calculated result. If the average was 7.0 or more, print the message "Aluno aprovado." (Approved Student). If the average was less than 5.0, print the message: "Aluno reprovado." (Reproved Student). If the average was between 5.0 and 6.9, including these, the program must print the message "Aluno em exame." (In exam student).
Solution
Solution Way:Here ,You have to find the average according with these number's given weights.At First we will take four double type variables.Then we will multiply each with it's weights.Then divide the total value with total weights. Then print some message as their requirements.In One condition you have to take another user input than repeat once. See my code for more understanding .Don't copy ,try yourself.
C programming code to solve uri beginner level problems.Easy coding.
Read four numbers (N1, N2, N3, N4), which one with 1 digit after the decimal point, corresponding to 4 scores obtained by a student. Calculate the average with weights 2, 3, 4 e 1 respectively, for these 4 scores and print the message "Media: " (Average), followed by the calculated result. If the average was 7.0 or more, print the message "Aluno aprovado." (Approved Student). If the average was less than 5.0, print the message: "Aluno reprovado." (Reproved Student). If the average was between 5.0 and 6.9, including these, the program must print the message "Aluno em exame." (In exam student).
In case of exam, read one more score. Print the message "Nota do exame: "
(Exam score) followed by the
typed score. Recalculate the average (sum the exam
score with the previous calculated average and divide by 2)
and print the message “Aluno aprovado.” (Approved student) in case of average 5.0 or more)
or "Aluno reprovado." (Reproved student) in case of average 4.9 or less. For these 2 cases (approved or reproved after the exam) print the message "Media final: " (Final average) followed by the final average for this student in the last line.
Input
The input contains four floating point numbers that represent the students' grades.
Output
Solution
#include<stdio.h>
int main()
{
double N1,N2,N3,N4,N5,avr;
scanf("%lf%lf%lf%lf",&N1,&N2,&N3,&N4);
avr = ((N1*2)+(N2*3)+(N3*4)+(N4*1))/10.0;
printf("Media: %0.1lf\n",avr);
if(avr >= 7.0)
printf("Aluno aprovado.\n");
if(avr < 5.0)
printf("Aluno reprovado.\n");
if(avr >= 5.0 && avr<7.0){
printf("Aluno em exame.\n");
scanf("%lf",&N5);
printf("Nota do exame: %0.1lf\n",N5);
avr=(avr+N5)/2.0;
if(avr >= 5.0)
printf("Aluno aprovado.\n");
if(avr<5.0)
printf("Aluno reprovado.\n");
printf("Media final: %0.1lf\n",avr);}
return 0;
}
int main()
{
double N1,N2,N3,N4,N5,avr;
scanf("%lf%lf%lf%lf",&N1,&N2,&N3,&N4);
avr = ((N1*2)+(N2*3)+(N3*4)+(N4*1))/10.0;
printf("Media: %0.1lf\n",avr);
if(avr >= 7.0)
printf("Aluno aprovado.\n");
if(avr < 5.0)
printf("Aluno reprovado.\n");
if(avr >= 5.0 && avr<7.0){
printf("Aluno em exame.\n");
scanf("%lf",&N5);
printf("Nota do exame: %0.1lf\n",N5);
avr=(avr+N5)/2.0;
if(avr >= 5.0)
printf("Aluno aprovado.\n");
if(avr<5.0)
printf("Aluno reprovado.\n");
printf("Media final: %0.1lf\n",avr);}
return 0;
}
Solution Way:Here ,You have to find the average according with these number's given weights.At First we will take four double type variables.Then we will multiply each with it's weights.Then divide the total value with total weights. Then print some message as their requirements.In One condition you have to take another user input than repeat once. See my code for more understanding .Don't copy ,try yourself.
C programming code to solve uri beginner level problems.Easy coding.
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