URI ONLINE JUDGE SOLUTION 1015 - Distance Between Two Points

Problem:

Read the four values corresponding to the x and y axes of two points in the plane, p1 (x1, y1) and p2 (x2, y2) and calculate the distance between them, showing four decimal places after the comma, according to the formula:

Distance =

Input

The input file contains two lines of data. The first one contains two double values: x1 y1 and the second one also contains two double values with one digit after the decimal point: x2 y2.

Output


Calculate and print the distance value using the provided formula, with 4 digits after the decimal point.


 Solution:

 #include<stdio.h>
#include<math.h>
int main()
{
    double x1,x2,y1,y2,dis;
    scanf("%lf%lf%lf%lf",&x1,&x2,&y1,&y2);
    dis=sqrt(pow((y1-x1),2)+pow((y2-x2),2));
    printf("%0.4lf\n",dis);
    return 0;

}
Location: Bangladesh

Comments

Post a Comment

Popular posts from this blog

URI ONLINE JUDGE SOLUTION 1021 - Banknotes and Coins

Image
Problem Read a value of floating point with two decimal places. This represents a monetary value. After this, calculate the smallest possible number of notes and coins on which the value can be decomposed. The considered notes are of 100, 50, 20, 10, 5, 2. The possible coins are of 1, 0.50, 0.25, 0.10, 0.05 and 0.01. Print the message “NOTAS:” followed by the list of notes and the message “MOEDAS:” followed by the list of coins. Input The input file contains a value of floating point N (0 ≤ N ≤ 1000000.00). Output Print the minimum quantity of banknotes and coins necessary to change the initial value, as the given example. Solution #include<stdio.h> int main() {     int c[12],n,f,i,num[] = {100,50,20,10,5,2,100,50,25,10,5,1};     double x;     scanf("%lf",&x);     n = x;     f = x*100;     f = f%100;     printf("NOTAS:\n&q
Read more

URI ONLINE JUDGE SOLUTION 1040 - Average 3

Image
Problem Read four numbers (N 1 , N 2 , N 3 , N 4 ), which one with 1 digit after the decimal point, corresponding to 4 scores obtained by a student. Calculate the average with weights 2, 3, 4 e 1 respectively, for these 4 scores and print the message "Media: " (Average), followed by the calculated result. If the average was 7.0 or more, print the message "Aluno aprovado." (Approved Student). If the average was less than 5.0, print the message: "Aluno reprovado." (Reproved Student). If the average was between 5.0 and 6.9, including these, the program must print the message "Aluno em exame." (In exam student). In case of exam, read one more score. Print the message "Nota do exame: " (Exam score) followed by the typed score. Recalculate the average (sum the exam score with the previous calculated average and divide by 2) and print the message “Aluno aprovado.” (Approved student) in
Read more

URI ONLINE JUDGE SOLUTION 1036 - Bhaskara's Formula

Image
Problem Read 3 floating-point numbers. After, print the roots of bhaskara’s formula. If it's impossible to calculate the roots because a division by zero or a square root of a negative number, presents the message “Impossivel calcular” . Input Read 3 floating-point numbers A, B and C. Output Print the result with 5 digits after the decimal point or the message if it is impossible to calculate. Solution #include<stdio.h> #include<math.h> int main() {     double A,B,C,d,r1,r2;     scanf("%lf%lf%lf",&A,&B,&C);     d = B*B-4*A*C;     if(A != 0 && d>=0)     {         d = sqrt(d);         r1 = (d-B)/(2*A);         r2 = (-d-B)/(2*A);         printf("R1 = %0.5lf\nR2 = %0.5lf\n",r1,r2);     }     else printf("Impossivel calcular\n");     return 0; } Description: Here the problem is about a mathematical equation. We already know a equation ax^2 + bx + c=0 .You have to find the roots of
Read more