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URI ONLINE JUDGE SOLUTION 1021 - Banknotes and Coins

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Problem Read a value of floating point with two decimal places. This represents a monetary value. After this, calculate the smallest possible number of notes and coins on which the value can be decomposed. The considered notes are of 100, 50, 20, 10, 5, 2. The possible coins are of 1, 0.50, 0.25, 0.10, 0.05 and 0.01. Print the message “NOTAS:” followed by the list of notes and the message “MOEDAS:” followed by the list of coins. Input The input file contains a value of floating point N (0 ≤ N ≤ 1000000.00). Output Print the minimum quantity of banknotes and coins necessary to change the initial value, as the given example. Solution #include<stdio.h> int main() {     int c[12],n,f,i,num[] = {100,50,20,10,5,2,100,50,25,10,5,1};     double x;     scanf("%lf",&x);     n = x;     f = x*100;     f = f%100;     printf("NOTAS:\n&q
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URI ONLINE JUDGE SOLUTION 1040 - Average 3

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Problem Read four numbers (N 1 , N 2 , N 3 , N 4 ), which one with 1 digit after the decimal point, corresponding to 4 scores obtained by a student. Calculate the average with weights 2, 3, 4 e 1 respectively, for these 4 scores and print the message "Media: " (Average), followed by the calculated result. If the average was 7.0 or more, print the message "Aluno aprovado." (Approved Student). If the average was less than 5.0, print the message: "Aluno reprovado." (Reproved Student). If the average was between 5.0 and 6.9, including these, the program must print the message "Aluno em exame." (In exam student). In case of exam, read one more score. Print the message "Nota do exame: " (Exam score) followed by the typed score. Recalculate the average (sum the exam score with the previous calculated average and divide by 2) and print the message “Aluno aprovado.” (Approved student) in
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URI ONLINE JUDGE SOLUTION 1036 - Bhaskara's Formula

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Problem Read 3 floating-point numbers. After, print the roots of bhaskara’s formula. If it's impossible to calculate the roots because a division by zero or a square root of a negative number, presents the message “Impossivel calcular” . Input Read 3 floating-point numbers A, B and C. Output Print the result with 5 digits after the decimal point or the message if it is impossible to calculate. Solution #include<stdio.h> #include<math.h> int main() {     double A,B,C,d,r1,r2;     scanf("%lf%lf%lf",&A,&B,&C);     d = B*B-4*A*C;     if(A != 0 && d>=0)     {         d = sqrt(d);         r1 = (d-B)/(2*A);         r2 = (-d-B)/(2*A);         printf("R1 = %0.5lf\nR2 = %0.5lf\n",r1,r2);     }     else printf("Impossivel calcular\n");     return 0; } Description: Here the problem is about a mathematical equation. We already know a equation ax^2 + bx + c=0 .You have to find the roots of
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